History homework help

##color(blue)(“Fahrenheit temperature “=(29xx9/5)+32 = 84.2^o F )##

The numbers to remember are 5, 9 and 32
Fahrenheit are the lager number when comparing like temperature for like So to convert Centigrade to Fahrenheit you need to make the numbers bigger so you multiply by ##9/5##. To go from Fahrenheit to centigrade you are making the numbers smaller so you multiply by ##5/9##
All you need to remember now is that freezing point for each is different.
Centigrade freezing point is ##0^o##
Fahrenheit freezing point is ##32^o##
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##color(blue)(“Using this information to answer your question”)##
We are going from Centigrade to Fahrenheit so it is small number to large. So we have ##color(blue)(xx9/5)##
We are changing melting point from 0 on 1 scale to 32 on a different scale so we now have:
##color(blue)(xx9/5+32)##
Thus the full conversion is:
##color(blue)(“Fahrenheit temperature “=(29xx9/5)+32 = 84.2^o F )##